For the rule y= 4 - x2, calculate the y-values that complete the table belowThe first value is given for you.IN (x) -3 -2 -1 0 1 2 3OUT (y) -5
Accepted Solution
A:
Answer:[tex]\begin{center}\begin{tabular}{ c| c } x & y=4-x^2 \\ -3 & -5 \\ -2 & 0\\-1 & 3 \\ 0 &4 \\ 1&3\\2&0\\3&-5\end{tabular}\end{center}[/tex]Step-by-step explanation:The given function is [tex]y=4-x^2[/tex]When x=-2 we have [tex]y=4-(-2)^2=4-4=0[/tex]When x=-1 we have [tex]y=4-(-1)^2=4-1=3[/tex]When x=0 we have [tex]y=4-(0)^2=4-0=4[/tex]When x=1 we have [tex]y=4-(1)^2=4-1=3[/tex]When x=2 we have [tex]y=4-(2)^2=4-4=0[/tex]When x=3 we have [tex]y=4-(3)^2=4-9=-5[/tex]The complete table is[tex]\begin{center}\begin{tabular}{ c| c } x & y=4-x^2 \\ -3 & -5 \\ -2 & 0\\-1 & 3 \\ 0 &4 \\ 1&3\\2&0\\3&-5\end{tabular}\end{center}[/tex]